//?P_C.cpp?:?Defines?the?class?behaviors?for?the?application.
//

#include?“stdafx.h“
#include?“P_C.h“
#include?“P_CDlg.h“

#ifdef?_DEBUG
#define?new?DEBUG_NEW
#define?M?10
#undef?THIS_FILE
static?char?THIS_FILE[]?=?__FILE__;
#endif
#define?WM_UPDATEDATA???WM_USER?+?1
/////////////////////////////////////////////////////////////////////////////
//?CP_CApp

BEGIN_MESSAGE_MAP（CP_CApp?CWinApp）
	//{{AFX_MSG_MAP（CP_CApp）
		//?NOTE?-?the?ClassWizard?will?add?and?remove?mapping?macros?here.
		//????DO?NOT?EDIT?what?you?see?in?these?blocks?of?generated?code!
	//}}AFX_MSG
	ON_COMMAND（ID_HELP?CWinApp::onhelp）
END_MESSAGE_MAP（）

/////////////////////////////////////////////////////////////////////////////
//?CP_CApp?construction

CP_CApp::CP_CApp（）
{
	//?TODO:?add?construction?code?here
	//?Place?all?significant?initialization?in?InitInstance
}

/////////////////////////////////////////////////////////////////////////////
//?The?one?and?only?CP_CApp?object

CP_CApp?theApp;
?int?in??;???//?生產者放置產品的位置
?int?out;?//?消費者取產品的位置
//sem_t?empty_sem;?//?同步信號量，當滿了時阻止生產者放產品
?HANDLE?empty_sem;
//sem_t?full_sem;???//?同步信號量，當沒產品時阻止消費者消費
?HANDLE?full_sem;
//pthread_mutex_t?mutex;?//?互斥信號量，?一次只有一個線程訪問緩沖
?HANDLE?mutex;

?int?ID_producer;
?int?ID_consumer;
?int?buff[M];
CWinThread*?pcwinthread1;
CWinThread*?pcwinthread2;
CWinThread*?pcwinthread3;
CWinThread*?ccwinthread1;
CWinThread*?ccwinthread2;
CWinThread*?ccwinthread3;

CString?str_display;
CString?str_buff;


UINT?Producer（?LPVOID?pParam?）{
	//生產者
	CP_CDlg*???pdlg=（CP_CDlg*）pParam;

	int?idp?=?ID_producer?;
	CString?s1;
	CString?s2;

?while（1）
?{
????//?用sleep的數量可以調節生產和消費的速度，便于觀察
???

?//確認有空緩沖區可供生產，同時將空位置數empty減1；用于生產者和消費者的同步；
?WaitForSingleobject（empty_sem-1）;
???????
??//互斥訪問下一個可用于生產的空臨界區，實現寫寫互斥；
??WaitForSingleobject（mutex-1）;
??
??//這二句如果顛倒的話可能出現一種異常情況
?
?//當進入了緩沖區為滿時顛倒之后會對緩沖區先加鎖然后進程由于緩沖區為買沒法生產產品在這里被阻塞而消費者又無法獲得緩沖區的鎖進入緩沖區因而會出現死鎖
??
????in?=?in?%?M;
????//printf（“product%d?in?%d.?like:?\t“?id?in）;
????s1?=“product“;
	s2.Format（“%d“idp）;
	s1?=?s1?+?s2;
	s2.Format（“%d“in+1）;
	s1?=?s1?+?“?in?“?+?s2?+?“\r\n“;
	str_display?=?str_display+s1;

????buff[in]?=?1;?
	pdlg->SendMessage（WM_UPDATEDATA）;
???
????++in;
????ReleaseMutex（mutex）;
????ReleaseSemaphore（full_sem1NULL）;

	Sleep（3000）;
?}	?
	?return?0;

}
UINT?Consumer（?LPVOID?pParam?）{
	//消費者
	CP_CDlg*???pdlg=（CP_CDlg*）pParam;
	int?idc?=?ID_consumer;
	
	CString?s2;
	
	CString?s1;
????while（1）
?{
????//?用sleep的數量可以調節生產和消費的速度，便于觀察
????
?
????WaitForSingleobject（full_sem-1）;?????
	//??這二句如果顛倒的話可能出現一種異常情況
?
?//當進入了緩沖區為空時顛倒之后會對緩沖區先加鎖然后進程由于緩沖區為空沒發消費產品在這里被阻塞而生產者又無法獲得緩沖區的鎖進入緩沖區因而會出現死鎖
?
????WaitForSingleobject（mutex-1）;

????out?=?out?%?M;
??//printf（“prochase%d?in?%d.?like:?\t“?id?out）;
????s1?=“consum“;
	s2.Format（“%d“idc）;
	s1?=?s1?+?s2;
	s2.Format（“%d“out+1）;
	s1?=?s1?+?“?in?“?+?s2?+?“\r\n“;
	str_display?=?str_displ

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件?????114770??2010-06-27?14:14??P_C\Debug\P_C.exe

?????文件?????361980??2010-06-27?14:14??P_C\Debug\P_C.ilk

?????文件??????28285??2010-06-27?14:13??P_C\Debug\P_C.obj

?????文件????5502316??2010-06-26?16:14??P_C\Debug\P_C.pch

?????文件?????410624??2010-06-27?14:14??P_C\Debug\P_C.pdb

?????文件???????3000??2010-06-27?14:11??P_C\Debug\P_C.res

?????文件??????52255??2010-06-27?14:14??P_C\Debug\P_CDlg.obj

?????文件?????105744??2010-06-26?16:14??P_C\Debug\StdAfx.obj

?????文件?????214016??2010-06-27?14:14??P_C\Debug\vc60.idb

?????文件?????372736??2010-06-27?14:14??P_C\Debug\vc60.pdb

?????文件??????36272??2010-06-27?14:06??P_C\P_C.APS

?????文件???????1545??2010-06-27?14:14??P_C\P_C.clw

?????文件???????4605??2010-06-27?13:44??P_C\P_C.cpp

?????文件???????4105??2010-06-26?16:06??P_C\P_C.dsp

?????文件????????514??2010-06-26?16:06??P_C\P_C.dsw

?????文件???????1291??2010-06-26?16:06??P_C\P_C.h

?????文件??????58368??2010-06-27?14:14??P_C\P_C.ncb

?????文件??????54784??2010-06-27?14:14??P_C\P_C.opt

?????文件????????946??2010-06-27?14:14??P_C\P_C.plg

?????文件???????6077??2010-06-27?14:06??P_C\P_C.rc

?????文件????????327??2010-06-27?09:26??P_C\P_C.sln

????..A..H.??????6656??2010-06-27?09:26??P_C\P_C.suo

?????文件??????12612??2010-06-27?14:14??P_C\P_CDlg.cpp

?????文件???????1790??2010-06-27?14:12??P_C\P_CDlg.h

?????文件???????3525??2010-06-26?16:06??P_C\ReadMe.txt

?????文件???????1078??2010-06-26?16:06??P_C\res\P_C.ico

?????文件????????395??2010-06-26?16:06??P_C\res\P_C.rc2

?????文件???????1095??2010-06-27?13:19??P_C\resource.h

?????文件????????205??2010-06-26?16:06??P_C\StdAfx.cpp

?????文件???????1054??2010-06-26?16:06??P_C\StdAfx.h

............此處省略6個文件信息