資源簡介
用c++實現的簡單xml解析,請將xml文件放在e盤

代碼片段和文件信息
//?stdafx.cpp?:?只包括標準包含文件的源文件
//?xmlsampie1.pch?將作為預編譯頭
//?stdafx.obj?將包含預編譯類型信息
#include?“stdafx.h“
//?TODO:?在?STDAFX.H?中
//?引用任何所需的附加頭文件,而不是在此文件中引用
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件?????????210??2014-11-05?09:16??xm
?????文件????????2970??2014-11-05?10:32??xm
?????目錄???????????0??2014-11-11?17:29??xm
?????目錄???????????0??2014-11-11?17:29??xm
?????文件???????71680??2014-11-05?09:46??xm
?????文件??????577652??2014-11-05?09:46??xm
?????文件?????1240064??2014-11-05?09:46??xm
?????目錄???????????0??2014-11-11?17:29??xm
?????目錄???????????0??2014-11-11?17:29??xm
?????文件????????6304??2014-11-05?09:46??xm
?????文件??????123966??2012-11-06?10:01??xm
?????文件??????????67??2014-11-05?09:46??xm
?????文件???????11849??2014-11-05?09:17??xm
?????文件??????527360??2014-11-05?09:46??xm
?????文件??????675840??2014-11-05?09:46??xm
?????文件?????????663??2014-11-05?09:19??xm
?????文件?????????728??2014-11-05?09:19??xm
?????文件?????????621??2014-11-05?09:46??xm
?????文件??????162362??2014-11-05?09:46??xm
?????文件?????3211264??2014-11-05?09:17??xm
?????文件????????1201??2014-11-05?09:03??xm
?????文件?????????215??2014-11-05?09:03??xm
?????文件?????????233??2014-11-05?09:03??xm
?????文件?????????498??2014-11-05?09:03??xm
?????文件????????2797??2014-11-11?17:30??xm
?????文件????????4507??2014-11-05?09:03??xm
?????文件????????1403??2014-11-05?11:46??xm
?????文件?????6728704??2014-11-05?11:46??xm
?????文件?????????896??2014-11-05?09:17??xm
?????文件????????7680??2014-11-05?11:46??xm
?????文件???????81408??2014-11-05?09:06??xm
............此處省略0個文件信息
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