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  • 大小: 4KB
    文件類型: .m
    金幣: 2
    下載: 1 次
    發布日期: 2021-05-15
  • 語言: Matlab
  • 標簽: ??

資源簡介

matlab編寫的圖像重建迭代算法,ART重建,給出了重建結果。

資源截圖

代碼片段和文件信息

clear?all;
clc;
I=phantom(256);
imshow(I);
theta1=0:179;
[R1xp1]?=?radon(I?theta1);
g=zeros(165536);
for?i=1:180
????if?(mod((i-1)2)==0)
????????Q(i)=(i+1)/2;
????????O(:i)=R1(:((i+1)/2));
????else?
????????Q(i)=90+i/2;
????????O(:i)=R1(:(90+i/2));
????end
end
for?y=1:180
????for?x=1:367
????????i=(y-1)*367+x;
????????p(i)=O(xy);
????end
end
for?M=1:180*367
????a=fix((M-1)/367)+1;
????theta=Q(a);
????t=mod((M-1)367)+1;
????A=cos((theta-1)*pi/180);
????B=sin((theta-1)*pi/180);
????C=-(t-184);
????if?(theta~=1)&&(theta~=91)
????i=1;????
????x=-128;
????y=-(A/B)*x-C/B;
????if((y<=128)&&(y>=-128))
????????tem(i)=x;
????????i=i+1;
????????tem(i)=y;
????????i=i+1;
????end
????x=128;
????y=-(A/B)*x-C/B;
????if((y<=128)&&(y>=-128))
????????tem(i)=x;
????????i=i+1;
????????tem(i)=y;
????????i=i+1;
????end;
????y=-128;
????x=-(B/A)*y-C/A;
????if((x<=128)&&(x>=-128))
????????tem(i)=x;
????????i=i+1;
????????tem(i)=y;
????????i=i+1;
????end
????y=128;
?????x=-(B/A)*y-C/A;
?????if((x<=128)&&(x>=-128))
????????tem(i)=x;
????????i=i+1;
????????tem(i)=y;
????????i=i+1;
?????end
????end
????if(theta==91)
????????????tem(1)=-128;
????????????tem(2)=-C;
????????????tem(3)=128;
????????????tem(4)=-C;
????????????
????end
????????if(theta==1)
????????????tem(1)=-C;
????????????tem(2)=-128;
????????????tem(3)=-C;
????????????tem(4)=128;
????????????
????????end
?????????if(tem(1)>tem(3))
?????????????tem(1)=ceil(tem(1));
?????????????tem(3)=floor(tem(3));
?????????????temp=tem(1);
?????????????tem(1)=tem(3);
?????????????tem(3)=temp;
????????
?????????end
?????????if(tem(3)>tem(1))
?????????????tem(3)=ceil(tem(3));
?????????????tem(1)=floor(tem(1));
?????????????
?????????end
?????????if(tem(2)>tem(4))
?????????????tem(2)=ceil(tem(2));
?????????????tem(4)=floor(tem(4));
?????????????temp=tem(2);
?????????????tem(

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