function?[Mmdf]=fftseq（mtzdf）
fz=1/tz;
if?nargin==2
????n1=0;
else?n1=fz/df;
end
n2=length（m）;
n=2^（max（nextpow2（n1）nextpow2（n2）））;
M=fft（mn）;?????????
m=[mzeros（1n-n2）];
df=fz/n;

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????197??2008-03-28?21:22??fftseq.m

?????文件???????1294??2008-04-04?14:18??lowsapple.m

?????文件????????447??2008-04-02?20:15??pam.m

-----------?---------??----------?-----??----

?????????????????1938????????????????????3