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資源簡(jiǎn)介

內(nèi)點(diǎn)法最優(yōu)潮流MATLAB算法: %節(jié)點(diǎn)數(shù)據(jù)處理 N=Node(:,1);%節(jié)點(diǎn)號(hào) Type=Node(:,2);%節(jié)點(diǎn)類型 Uamp=Node(:,3);%節(jié)點(diǎn)電壓幅值 Dlta=Node(:,4);%節(jié)點(diǎn)電壓相角 Pd=Node(:,5);%節(jié)點(diǎn)負(fù)荷有功。

資源截圖

代碼片段和文件信息


clear;
%clc;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%初始化%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

%數(shù)據(jù)加載
n=input(‘請(qǐng)輸入要計(jì)算的節(jié)點(diǎn)系統(tǒng)(5):‘)
????load?Node5.txt;%節(jié)點(diǎn)數(shù)據(jù)
????load?Branch5.txt;%支路數(shù)據(jù)
????load?Generator5.txt;%發(fā)電機(jī)數(shù)據(jù)
????Node=Node5;
????Branch=Branch5;
????Generator=Generator5;

%節(jié)點(diǎn)數(shù)據(jù)處理
N=Node(:1);%節(jié)點(diǎn)號(hào)
Type=Node(:2);%節(jié)點(diǎn)類型
Uamp=Node(:3);%節(jié)點(diǎn)電壓幅值
Dlta=Node(:4);%節(jié)點(diǎn)電壓相角
Pd=Node(:5);%節(jié)點(diǎn)負(fù)荷有功
Qd=Node(:6);%節(jié)點(diǎn)負(fù)荷無(wú)功
Pg=Node(:7);%節(jié)點(diǎn)出力有功
Qg=Node(:8);%節(jié)點(diǎn)出力無(wú)功
Umax=Node(:9);%節(jié)點(diǎn)電壓幅值上限
Umin=Node(:10);%節(jié)點(diǎn)電壓幅值下限
Bc=Node(:11);%節(jié)點(diǎn)補(bǔ)償電容電納值
%支路數(shù)據(jù)處理
Nbr=Branch(:1);%支路號(hào)
Nl=Branch(:2);%支路首節(jié)點(diǎn)
Nr=Branch(:3);%支路末節(jié)點(diǎn)
R=Branch(:4);%支路電阻
X=Branch(:5);%支路電抗
Z=R+1i*X;%支路阻抗=支路電阻+支路電抗
Bn=Branch(:6);%支路對(duì)地電納
K=Branch(:7);%支路變壓器變比,0表示無(wú)變壓器
Ptmax=Branch(:8);%線路傳輸功率上限

%發(fā)電機(jī)數(shù)據(jù)處理
Ng=Generator(:1);%發(fā)電機(jī)序號(hào)
Nbus=Generator(:2);%所在母線號(hào)
Pumax=Generator(:3);%發(fā)電機(jī)有功出力上界
Qumax=Generator(:4);%發(fā)電機(jī)無(wú)功出力上界
Pumin=Generator(:5);%發(fā)電機(jī)有功出力下界
Qumin=Generator(:6);%發(fā)電機(jī)無(wú)功出力下界
a2=Generator(:7);%燃料耗費(fèi)曲線二次系數(shù)
a1=Generator(:8);%燃料耗費(fèi)曲線一次系數(shù)
a0=Generator(:9);%燃料耗費(fèi)曲線常數(shù)項(xiàng)

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

n=length(N);%節(jié)點(diǎn)個(gè)數(shù)
ng=length(Ng);%發(fā)電機(jī)臺(tái)數(shù)
nbr=length(Nbr);%支路個(gè)數(shù)

x=zeros(2*(ng+n)1);%控制變量+狀態(tài)變量
x(1:ng)=Pg(Nbus);
x(ng+1:2*ng)=Qg(Nbus);
x((2*ng+2):2:2*(ng+n))=Uamp;
x((2*ng+1):2:2*(ng+n)-1)=Dlta;
l=0.8*ones(2*ng+n+nbr1);%松弛變量
u=1.1*ones(2*ng+n+nbr1);%松弛變量

w=-1.5*ones(2*ng+n+nbr1);%拉格朗日乘子
z=ones(2*ng+n+nbr1);%拉格朗日乘子
y=zeros(2*n1);%拉格朗日乘子
y(1:2:2*n-1)=1e-3;
y(2:2:2*n)=-1e-3;


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%計(jì)算不等式約束的上下限%%%%%%%%%%%%%%%%%%%%%%%%
%gmin
gmin=zeros(2*ng+n+nbr1);
gmin(1:ng)=Pumin;
gmin(ng+1:2*ng)=Qumin;
gmin(2*ng+1:2*ng+n)=Umin;
gmin(2*ng+n+1:2*ng+n+nbr)=-Ptmax;??
%gmax
gmax=zeros(2*ng+n+nbr1);
gmax(1:ng)=Pumax;
gmax(ng+1:2*ng)=Qumax;
gmax(2*ng+1:2*ng+n)=Umax;
gmax(2*ng+n+1:2*ng+n+nbr)=Ptmax;????????
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%形成導(dǎo)納矩陣%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

Y=zeros(nn);
%%%%%%%%%%%%%%%%%%%%計(jì)算非對(duì)角元素%%%%%%%%%%%%%%%%%%%%%
for?ii=1:nbr
????if?K(ii)==0%非變壓器支路
????????Y(Nl(ii)Nr(ii))=-1/Z(ii);
????????Y(Nr(ii)Nl(ii))=Y(Nl(ii)Nr(ii));
????else%變壓器支路
????????Y(Nl(ii)Nr(ii))=-1/Z(ii)/K(ii);
????????Y(Nr(ii)Nl(ii))=?Y(Nl(ii)Nr(ii));
????end
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

%%%%%%%%%%%%%%%%%%%%計(jì)算對(duì)角元素%%%%%%%%%%%%%%%%%%%%%%
for?ii=1:n%將支路導(dǎo)納加入到對(duì)角元素中
????for?jj=1:nbr
????????if?K(jj)==0&&(Nl(jj)==ii||Nr(jj)==ii)%非變壓器支路
????????????????Y(iiii)=Y(iiii)+1/Z(jj);
????????else?if?K(jj)~=0&&(Nl(jj)==ii||Nr(jj)==ii)%變壓器支路
????????????????Y(iiii)=Y(iiii)+1/Z(jj)/K(jj);
????????????end
????????end
????end
end

for?ii=1:nbr%將對(duì)地電納加入到對(duì)角元素中
????if?K(ii)==0%非變壓器支路
????????Y(Nl(ii)Nl(ii))=Y(Nl(ii)Nl(ii))+1i*Bn(ii);
????????Y(Nr(ii)Nr(ii))=Y(Nr(ii)Nr(ii))+1i*Bn(ii);
????else%變壓器支路????????
????????Y(Nr(ii)Nr(ii))=Y(Nr(ii)Nr(ii))+(K(ii)-1)/K(ii)/Z(ii);
????????Y(Nl(ii)Nl(ii))=Y(Nl(ii)Nl(ii))+(1-K(ii))/K(ii)/K(ii)/Z(ii);
????end
end

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