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資源簡介

BDBR表示在同樣的客觀質量下,較優的編碼方法可以節省的碼率百分比,其中BDBR越小,當前編碼器的壓縮性能越佳;BD-PSNR表示在同等碼率下,兩種編碼條件下壓縮后視頻PSNR值的差異,其中BD-PSNR值越大,當前編碼器質量損失越小。 計算視頻質量BDBR 和BD-PSNR的matlab代碼,運行正確。

資源截圖

代碼片段和文件信息

function?avg_diff?=?bjontegaard(R1PSNR1R2PSNR2mode)

%BJONTEGAARD????Bjontegaard?metric?calculation
%???Bjontegaard‘s?metric?allows?to?compute?the?average?gain?in?PSNR?or?the
%???average?per?cent?saving?in?bitrate?between?two?rate-distortion
%???curves?[1].
%???Differently?from?the?avsnr?software?package?or?VCEG?Excel?[2]?plugin?this
%???tool?enables?Bjontegaard‘s?metric?computation?also?with?more?than?4?RD
%???points.
%
%???R1PSNR1?-?RD?points?for?curve?1
%???R2PSNR2?-?RD?points?for?curve?2
%???mode?-?
%???????‘dsnr‘?-?average?PSNR?difference
%???????‘rate‘?-?percentage?of?bitrate?saving?between?data?set?1?and
%????????????????data?set?2
%
%???avg_diff?-?the?calculated?Bjontegaard?metric?(‘dsnr‘?or?‘rate‘)
%???
%???(c)?2010?Giuseppe?Valenzise
%
%???References:
%
%???[1]?G.?Bjontegaard?Calculation?of?average?PSNR?differences?between
%???????RD-curves?(VCEG-M33)
%???[2]?S.?Pateux?J.?Jung?An?excel?add-in?for?computing?Bjontegaard?metric?and
%???????its?evolution

%?convert?rates?in?logarithmic?units
lR1?=?log(R1);
lR2?=?log(R2);

switch?lower(mode)
????case?‘dsnr‘
????????%?PSNR?method
????????p1?=?polyfit(lR1PSNR13);
????????p2?=?polyfit(lR2PSNR23);

????????%?integration?interval
????????min_int?=?min([lR1;?lR2]);
????????max_int?=?max([lR1;?lR2]);

????????%?find?integral
????????p_int1?=?polyint(p1);
????????p_int2?=?polyint(p2);

????????int1?=?polyval(p_int1?max_int)?-?polyval(p_int1?min_int);
????????int2?=?polyval(p_int2?max_int)?-?polyval(p_int2?min_int);

????????%?find?avg?diff
????????avg_diff?=?(int2-int1)/(max_int-min_int);

????case?‘rate‘
????????%?rate?method
????????p1?=?polyfit(PSNR1lR13);
????????p2?=?polyfit(PSNR2lR23);

????????%?integration?interval
????????min_int?=?min([PSNR1;?PSNR2]);
????????max_int?=?max([PSNR1;?PSNR2]);

????????%?find?integral
????????p_int1?=?polyint(p1);
????????p_int2?=?polyint(p2);

????????int1?=?polyval(p_int1?max_int)?-?polyval(p_int1?min_int);
????????int2?=?polyval(p_int2?max_int)?-?polyval(p_int2?min_int);

????????%?find?avg?diff
????????avg_exp_diff?=?(int2-int1)/(max_int-min_int);
????????avg_diff?=?(exp(avg_exp_diff)-1)*100;
end

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????2219??2014-02-12?13:09??bjontegaard\bjontegaard.m

?????文件???????1318??2014-02-12?13:09??bjontegaard\license.txt

?????文件????????445??2014-02-12?13:09??bjontegaard\test_bjontegaard.m

?????目錄??????????0??2019-01-16?17:58??bjontegaard

-----------?---------??----------?-----??----

?????????????????3982????????????????????4


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