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%茍峻彬.?Mar?14?2018.?Class?Session?B
%?First?define?the?connection?matrix
A0=[0?1?0?1?1?0?0?0?0
???1?0?1?0?0?0?0?0?0
???1?0?0?0?0?1?0?0?0
???0?0?1?0?1?1?1?0?0
???0?0?1?1?0?0?0?0?1
???0?0?1?0?0?0?1?1?0
???1?0?0?0?1?0?0?1?0
???0?0?0?1?0?0?0?0?1
???0?0?0?1?0?0?1?0?0]
A1=sum（A0）;?%column?sum
A2=repmat（A1?91）?%將A2復制9行
A=A0./A2;?%This?will?normalize?the?columns
N=9;?%Nine?nodes?in?the?graph
%without?starting?over?from?bookmark/address?bar
d=1;?
N=size（A2）;?%get?the?number?of?columns?of?Matrix?A.
R0=ones（N1）;?R0=R0/sum（R0）;%initialize?R0
R20=A^20*R0?%Compute?the?value?after?20?iterations
%do?four?more?iterations?and?see?whether?the?results?are?different
R24=A^24*R0
%We?can?verify?that?20?iterations?vs?24?iterations?have?the?same?results.
R15=A^15*R0?%Compute?the?value?after?15?iterations
R16=A^16*R0?%Compute?the?value?after?16?iterations
%We?can?verify?that?16?iterations?vs?24?iterations?have?the?same
%resultsbut?15?iterations?have?a?little?difference?with?the?result?of?16
%iterations.
%So?16?iterations?are?OK.
%Result:RA=0.1526?RB=0.0772?RC=0.1054?RD=0.1589?RE=0.1070?RF=0.1090
%RG=0.1269?RH=0.0807?RI=0.0820
%Order?of?Popularity:D>A>G>F>E>C>I>H>B

%with?starting?over?from?bookmark/address?bar?we?consider?that?if?the
%extreme?positions?are?the?same?as?the?concept?of?“same“.
?d=0.85;
?R=R0;
?%do?8?iterations
?R=（1-d）/N+d*A*R;?R=（1-d）/N+d*A*R;?R=（1-d）/N+d*A*R;?R=