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  • 大小: 143KB
    文件類型: .rar
    金幣: 2
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    發布日期: 2021-06-11
  • 語言: Matlab
  • 標簽: 模式識別??

資源簡介

一個簡單的貝葉斯高斯分類的作業,用matlab編寫,入門用

資源截圖

代碼片段和文件信息

%讀入訓練集
clear?all;
close?all;
clc

D=load(‘data2.txt‘);

%計算初始EM的初始參數值
%??G?為類別數
%?class(1,G)?為類別集?class(1i)第i類的類標
%??D?訓練集?D為m*n,
class=[012];
G=3;
a=zeros(1G);
%?GG?為3維類別矩陣
[m?n]=size(D);
data=D(:1:n-1);
%GG1=[];
%GG2=[];
%GG3=[];
GG=zeros(mn-1G);
k=zeros(1G);
for?i=1:m
????for?j=1:G
????????if?D(in)==class(1j)
??????????????k(1j)=k(1j)+1;?????????%數據類別歸類
????????????GG(k(1j):j)=data(i:);
???????????break;
????????????%k(1j)=k(1j)+1;
????????end
????end
end


%====================先驗概率p(ci)
%初始化ai
mi=zeros(1G);
for?i=1:G
%?????[mmnn]=size(GG(::i));
%?????mi(1i)=mm-1;
%?????a(1i)=?mi(1i)/m;
?mi(1i)=k(1i);
?a(1i)=?mi(1i)/m;?????
end

%===================求均值
%初始化Ui
U=zeros(Gn-1);
?for?i=1:G
???for?j=1:mi(1i)
???????U(i:)=U(i:)+GG(j:i);
???end
?????U(i:)=U(i:)/mi(1i);
?end
????%==或者
????%??uu1=mean(GG(1:k(11):1));???y=GG(1:k(11):1);????是一個42*40?的矩陣,
????%??k(11)表示的是第一類的行數?%??均值是1*40的矩陣?1:k(11)?
????%??uu2=mean(GG(1:k(12):2));
????%??uu3=mean(GG(1:k(13):3));
????%??uu=[uu1;uu2;uu3];
?
%==========================初始化協方差?Cg?(矩陣)?
C=zeros(n-1n-1G);
for?i=1:G
????for?j=1:mi(1i)
????????C(::i)=C(::i)+(GG(j:i)-?U(i:))‘*(GG(j:i)-?U(i:));???%???行*列數?為屬性個數40*40
????end
????C(::i)=C(::i)/mi(1i);
end



%參數已確定,進行類別判斷

%讀入測試集
test=load(‘testdata.txt‘);
testdata=test(:1:n-1);
[mtestntest]=size(testdata);
class_p=zeros(Gmtest);

?
?
???
????for?i=1:G
????????for?j=1:mtest
????????????for?kk=1:G????
???????????class_p(ij)=class_p(ij)+a(1kk)*GaoSi_probability(U(kk:)‘C(::kk)testdata(j:)‘);????%分母:?對i有3個類別值進行求和p(ci)p(testdata(j:)‘|ci)
????????????end
?????????????class_p(ij)=a(1i)*GaoSi_probability(U(i:)‘C(::i)testdata(j:)‘)/class_p(ij);??%?p(ci|testdata(j:)‘)
????????end
????end
???
forecast_class=zeros(mtest1);
for?i=1:mtest
???guodu=find(class_p(:i)==max(class_p(:i)));??%找到p(ci|testdata(j:)‘)中的最大一個的位置
???forecast_class(i1)=class(guodu(11));?????%class=[0?1?2];
end
resultdata=[testdata?forecast_class(:1)];

%計算準確率
correct_probability=0;
????
for?i=1:mtest
????if?test(in)==forecast_class(i1)
????????correct_probability=correct_probability+1;
????end
end

correct_probability=correct_probability/mtest



?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????2480??2011-12-05?11:18??bayes\byes.m

?????文件??????99838??2011-07-25?16:30??bayes\data.txt

?????文件??????45998??2011-07-25?16:30??bayes\data1.txt

?????文件??????28078??2011-07-25?16:30??bayes\data2.txt

?????文件????????416??2011-12-05?11:47??bayes\GaoSi_probability.m

?????文件?????138375??2011-07-25?16:30??bayes\testdata.txt

?????文件?????131535??2011-07-25?16:30??bayes\undata.txt

?????目錄??????????0??2011-12-23?11:07??bayes

-----------?---------??----------?-----??----

???????????????446720????????????????????8


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