function?p=nafit（xym）
A=zeros（m+1m+1）;
for?i=0:m
????for?j=0:m
????????A（i+1j+1）=sum（x.^（i+j））;
????end
????b（i+1）=sum（x.^i.*y）;
end
a=A\b‘;
p=fliplr（a‘）;

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2020-10-10?12:53??數(shù)值分析上機(jī)\
?????目錄???????????0??2020-10-10?12:55??數(shù)值分析上機(jī)\第一次\
?????文件??????119296??2020-10-08?23:04??數(shù)值分析上機(jī)\第一次\1.doc
?????文件????????7869??2020-10-10?12:51??數(shù)值分析上機(jī)\第一次\1.zip
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\3\
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\3\6-18\
?????文件?????????167??2019-11-26?22:34??數(shù)值分析上機(jī)\第三次\3\3\6-18\nafit.m
?????文件??????????80??2019-11-26?22:34??數(shù)值分析上機(jī)\第三次\3\3\6-18\p6_18.m
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\3\6-19\
?????文件?????????191??2019-11-26?22:36??數(shù)值分析上機(jī)\第三次\3\3\6-19\nafit1.m
?????文件?????????106??2019-11-26?22:36??數(shù)值分析上機(jī)\第三次\3\3\6-19\p6_19.m
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\3\6-20\
?????文件?????????167??2019-11-26?22:45??數(shù)值分析上機(jī)\第三次\3\3\6-20\nafit.m
?????文件??????????67??2019-11-26?22:45??數(shù)值分析上機(jī)\第三次\3\3\6-20\p6_20.m
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\3\6-3\
?????文件?????????543??2019-11-26?22:22??數(shù)值分析上機(jī)\第三次\3\3\6-3\cheby.m
?????文件??????????53??2019-11-26?22:22??數(shù)值分析上機(jī)\第三次\3\3\6-3\p6_3.m
?????目錄???????????0??2020-10-10?12:50??數(shù)值分析上機(jī)\第三次\3\3\6-6\
?????文件?????????492??2019-11-26?22:23??數(shù)值分析上機(jī)\第三次\3\3\6-6\cheby.m
?????文件??????????54??2019-11-26?22:24??數(shù)值分析上機(jī)\第三次\3\3\6-6\p6_6.m
?????文件??????116736??2020-10-08?23:15??數(shù)值分析上機(jī)\第三次\3.doc
?????目錄???????????0??2020-10-10?12:55??數(shù)值分析上機(jī)\第二次\
?????文件???????99328??2020-10-08?23:09??數(shù)值分析上機(jī)\第二次\2.doc
?????文件????????4392??2020-10-10?12:52??數(shù)值分析上機(jī)\第二次\2.zip
?????目錄???????????0??2020-10-10?12:54??數(shù)值分析上機(jī)\第四次\
?????文件???????83812??2020-10-10?12:54??數(shù)值分析上機(jī)\第四次\4.docx
?????文件???????13325??2020-10-10?12:54??數(shù)值分析上機(jī)\第四次\4.zip