資源簡介
學習 matlab 潮流計算編程簡單的入門程序 采用IEEE33節點 具有普遍性 采用配電網常用的前推回代潮流計算方法
代碼片段和文件信息
clc
clear?all;
format?short;
Z=[0??1??0.0922+j*0.047???100+j*60
???1??2??0.4930+j*0.2511??90+j*40
???2??3??0.3660+j*0.1864??120+j*80
???3??4??0.3811+j*0.1941??60+j*30?
???4??5??0.8190+j*0.7070??60+j*20
???5??6??0.1872+j*0.6188??200+j*100
???6??7??0.7114+j*0.2351??200+j*100
???7??8??1.0300+j*0.7400??60+j*20
???8??9??1.0440+j*0.7400??60+j*20
???9??10?0.1966+j*0.0650??45+j*30
???10?11?0.3744+j*0.1238??60+j*35
???11?12?1.4680+j*1.1550??60+j*35
???12?13?0.5416+j*0.7129??120+j*80
???13?14?0.5910+j*0.5260??60+j*10
???14?15?0.7463+j*0.5450??60+j*20
???15?16?1.2890+j*1.7210??60+j*20
???16?17?0.3720+j*0.5740??90+j*40
???1??18?0.1640+j*0.1565??90+j*40
???18?19?1.5042+j*1.3554??90+j*40
???19?20?0.4095+j*0.4784??90+j*40
???20?21?0.7089+j*0.9373??90+j*40
???2??22?0.4512+j*0.3083??90+j*50
???22?23?0.8980+j*0.7091??420+j*200
???23?24?0.8960+j*0.7011??420+j*200
???5??25?0.2030+j*0.1034??60+j*25
???25?26?0.2842+j*0.1447??60+j*25
???26?27?1.0590+j*0.9337??60+j*20
???27?28?0.8042+j*0.7006??120+j*70
???28?29?0.5075+j*0.2585??200+j*600
???29?30?0.9744+j*0.9630??150+j*70
???30?31?0.3105+j*0.3619??210+j*100
???31?32?0.3410+j*0.5362??60+j*40];%根據網絡拓撲結構,第一列為支路首節點,第二列為支路末節點,第三列為支路阻抗,第四列為節點負荷功率
%將參數化為標幺值進行計算(Sb=10MVA;Vb=12.66KV)
Sb=10;??
Vb=12.66;
Z(:4)=Z(:4)/(Sb*1000);
Z(:3)=Z(:3)*Sb/Vb^2;
???????????????????????%Start
[mn]=size(Z);
V=ones(m+11);
dU=ones(m1);
S=zeros(m+11);
Sr=Z(:4);
dSr=zeros(m1);
????
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