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資源簡介

matlab寫的rs分析法(重標極差),非常好。

資源截圖

代碼片段和文件信息

function?[logRSlogERSV]=RSana(xnmethodq)
%?Alexandros?Leontitsis
%?Department?of?Education
%?University?of?Ioannina
%?45110?-?Dourouti
%?Ioannina
%?Greece
%
%?University?e-mail:?me00743@cc.uoi.gr
%?Lifetime?e-mail:?leoaleq@yahoo.com
%?Homepage:?http://www.geocities.com/CapeCanaveral/Lab/1421
%
%?1?Jan?2004.
?
if?nargin<1?|?isempty(x)==1
???error(‘You?should?provide?a?time?series.‘);
else
???%?x?must?be?a?vector
???if?min(size(x))>1
??????error(‘Invalid?time?series.‘);
???end
???x=x(:);
???%?N?is?the?time?series?length
???N=length(x);
end
?
if?nargin<2?|?isempty(n)==1
???n=1;
else
???%?n?must?be?either?a?scalar?or?a?vector
???if?min(size(n))>1
??????error(‘n?must?be?either?a?scalar?or?a?vector.‘);
???end
???%?n?must?be?integer
???if?n-round(n)~=0
???????error(‘n?must?be?integer.‘);
???end
???%?n?must?be?positive
???if?n<=0
?????error(‘n?must?be?positive.‘);
???end
end
?
if?nargin<4?|?isempty(q)==1
???q=0;
else
????if?q==‘auto‘
????????t=autocorr(x1);
????????t=t(2);
????????q=((3*N/2)^(1/3))*(2*t/(1-t^2))^(2/3);
????else
????????%?q?must?be?a?scalar
????????if?sum(size(q))>2
????????????error(‘q?must?be?scalar.‘);
????????end
????????%?q?must?be?integer
????????if?q-round(q)~=0
????????????error(‘q?must?be?integer.‘);
????????end
????????%?q?must?be?positive
????????if?q<0
????????????error(‘q?must?be?positive.‘);
????????end
????end
end
?
?
for?i=1:length(n)
????
????%?Calculate?the?sub-periods
????a=floor(N/n(i));
????
????%?Make?the?sub-periods?matrix
????X=reshape(x(1:a*n(i))n(i)a);
????
????%?Estimate?the?mean?of?each?sub-period
????ave=mean(X);
????
????%?Remove?the?mean?from?each?sub-period
????cumdev=X-ones(n(i)1)*ave;
????
????%?Estimate?the?cumulative?deviation?from?the?mean
????cumdev=cumsum(cumdev);
????
????%?Estimate?the?standard?deviation
????switch?method
????case?‘Hurst‘
????????%?Hurst-Mandelbrot?variation
????????stdev=std(X);
????case?‘Lo‘
????????%?Lo?variation
????????for?j=1:a
????????????sq=0;
??????????

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