資源簡介
遞推最小二乘估計(RLS)及模型階次辨識(F-Test)matlab程序,可直接運行,結果分析見博客。

代碼片段和文件信息
function??K=calculateK(nLtheta)
temp1=0;
for?i=1:n
????temp1=temp1+theta(i);%a
end
temp=0;
for?i=(n+1):2*n
????temp=temp+theta(i);%b
end
K=temp/(1+temp1);
end
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2019-06-05?17:47??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\
?????文件?????????172??2019-05-22?08:32??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\calculateK.m
?????文件?????????186??2019-05-22?08:25??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\calculateRLS.m
?????文件?????????171??2019-05-22?08:40??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\calculateRLS1.m
?????文件?????????225??2019-05-22?08:40??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\calculateRLS2.m
?????文件?????????293??2019-05-20?19:14??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\createM1.m
?????文件?????????377??2019-05-20?19:11??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\createV1.m
?????文件?????????601??2019-05-22?09:20??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\F_Test.m
?????文件????????2062??2019-05-22?15:56??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\main1.m
?????文件?????????174??2019-05-21?15:53??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\plot1.m
?????文件?????????415??2019-05-22?10:54??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\plot2.m
?????文件?????????245??2019-05-21?16:28??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\plot31.m
?????文件????????1198??2019-05-22?09:02??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\RLS.m
?????文件?????????616??2019-05-21?21:12??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\RLS0.m
?????文件?????????139??2019-05-21?16:06??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\transform_u.m
?????文件?????????128??2019-05-22?10:32??遞推最小二乘估計(RLS)及模型階次辨識(F-Test)\transform_v.m
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