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  • 大小: 4KB
    文件類型: .rar
    金幣: 2
    下載: 0 次
    發布日期: 2023-12-04
  • 語言: Matlab
  • 標簽: emd??eemd??matlab??

資源簡介

經驗模態分析的matlab源程序,可以進行emd和eemd的計算。

資源截圖

代碼片段和文件信息

%?This?is?a?utility?program?being?called?by?“significance.m“.
%
%???function?PDF?=?dist_value(yPos?yBar?nDof)
%

function?PDF?=?dist_value(yPos?yBar?nDof)

%???function?PDF?=?dist_value2(yPos?yBar?nDof)
%
%???PDF:?a?normalized?output?array?
%???yPos:?An?input?array?at?which?PDF?values?are?calculated
% yBar:?The?expected?value?of?yPos?
% nDof:?The?number?of?degree?of?freedom
%
%
%?References?can?be?found?in?the?“Reference“?section.
%
%?The?code?is?prepared?by?Zhaohua?Wu.?For?questions?please?read?the?“Q&A“?section?or
%?contact
%???zwu@fsu.edu
%
ylen?=?length(yPos);
eBar?=?exp(yBar);

evalue=exp(yPos);

for?i=1:ylen
????tmp1?=?evalue(i)/eBar-yPos(i);
????tmp2?=?-tmp1*nDof*eBar/2;
????tmp3(i)?=?0.5*nDof*eBar*log(nDof)?+?tmp2;
end

rscale?=?max(tmp3);

tmp4?=?tmp3?-?rscale;

PDF=?exp(tmp4);



?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????847??2009-09-14?20:04??dist_value.m

?????文件???????2004??2009-09-14?20:03??eemd.m

?????文件???????2180??2009-09-14?20:04??extrema.m

?????文件???????1818??2009-09-14?20:04??ifndq.m

?????文件???????2938??2009-09-14?20:04??significance.m

-----------?---------??----------?-----??----

?????????????????9787????????????????????5


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