資源簡介
原創,感謝支持!本程序通過對傅里葉級數展開過程的可視化分析,利用MATLAB在繪圖、計算方面的優勢,將傅里葉的展開過程清晰地呈現出來,從而更好地幫助用戶理解傅里葉級數,為電類專業未來的學習打下良好基礎。

代碼片段和文件信息
function?calledit(hedit?hpoph_axes_3dh_axes_fh_axes_nhh_axes_zzwhich)
????ct?=?get(hedit‘string‘);
????vpop?=get?(hpop‘value‘);
????x=1;
????if~isempty(vpop)
????????popstr?=?{‘draw_all(3h_axes_3dh_axes_fh_axes_nhh_axes_zz);‘...
????????????‘draw_all(5h_axes_3dh_axes_fh_axes_nhh_axes_zz)‘...
????????????‘draw_all(9h_axes_3dh_axes_fh_axes_nhh_axes_zz)‘...
????????????‘draw_all(22h_axes_3dh_axes_fh_axes_nhh_axes_zz)‘};
????????cct?=?str2double(ct);
????????if?which
????????????eval(popstr{vpop})
????????else
????????????if?~isnan(cct)?&&?cct>0
????????????????eval([‘draw_all(‘ct‘h_axes_3dh_axes_fh_axes_nhh_axes_zz)‘])
????????????elseif?~isempty(ct)
????????????????errordlg(‘請輸入一個正阿拉伯數字,如:17‘‘提示‘);
????????????end
????????end
????end
end
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????815??2017-12-09?17:49??Source\calledit.m
?????文件????????275??2017-12-09?16:35??Source\draw_all.m
?????文件????????721??2017-12-12?19:56??Source\ex_fly_dt.m
?????文件????????359??2017-12-12?20:15??Source\ex_fly_f.m
?????文件???????1027??2017-12-12?19:56??Source\ex_fly_nh.m
?????文件???????1880??2017-12-12?20:15??Source\ex_fly_one.m
?????文件????????642??2017-12-12?20:12??Source\ex_fly_zz.m
?????文件????????401??2017-12-12?19:39??Source\ex_words.m
?????文件????????729??2017-12-09?17:27??Source\filesave.m
?????文件???????3254??2018-09-05?10:35??Source\main.m
?????文件????????240??2017-12-09?17:49??Source\radio_one_Callback.m
?????文件????????237??2017-12-09?17:49??Source\radio_two_Callback.m
?????文件???????2022??2018-09-05?12:38??Source\readme.md
?????文件?????202509??2018-09-05?10:29??Source\程序截圖.png
?????文件?????179159??2018-09-05?15:02??Source\程序說明.docx
?????目錄??????????0??2018-09-05?15:02??Source
-----------?---------??----------?-----??----
???????????????394270????????????????????16
- 上一篇:分布式預測控制程序
- 下一篇:MATLAB版大富翁完整版
評論
共有 條評論