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資源簡介

利用多項式糾正(一次項)進行幾何糾正,糾正過程采用反解法,重采樣方法采用雙線性內插。

資源截圖

代碼片段和文件信息

clear?all;
imfinfo(‘C:\Documents?and?Settings\Administrator\桌面\image\實習2-參考圖像.bmp‘)
imfinfo(‘C:\Documents?and?Settings\Administrator\桌面\image\實習2-待糾正圖像.bmp‘)
I1=imread(‘C:\Documents?and?Settings\Administrator\桌面\image\實習2-參考圖像.bmp‘);
I2=imread(‘C:\Documents?and?Settings\Administrator\桌面\image\實習2-待糾正圖像.bmp‘);

%%R1=I1(::1);
%G1=I1(::2);
%B1=I1(::3);

%R2=I2(::1);
%G2=I2(::2);
%B2=I2(::3);

%subplot(231);
%imshow(R2);
%subplot(232);
%imshow(G2);
%subplot(233);
%imshow(B2);

%參考圖像
y=[302?463?455?588?591?357]‘;
x=[161?551?587?623?641?611]‘;
%待糾正圖像
yy=[287?378?364?488?488?263]‘;
xx=[113?526?560?619?637?566]‘;

A=zeros(63);
for?m?=?1:6
????A(m1)?=?1;
????A(m2)?=?x(m);
????A(m3)?=?y(m);
end

delta_a?=?inv(A‘*A)*A‘*xx;
delta_b?=?

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????3375??2009-12-24?14:30??image1\new.asv

?????文件???????3375??2009-12-24?14:34??image1\new.m

?????文件???????4389??2009-12-24?14:52??image1\shixi3.asv

?????文件???????4386??2009-12-24?14:52??image1\shixi3.m

????..A.SH.?????17408??2009-12-23?15:59??image1\Thumbs.db

?????文件????1564606??2008-11-14?10:43??image1\實習2-參考圖像.bmp

?????文件????1160766??2008-11-13?16:41??image1\實習2-待糾正圖像.bmp

?????文件?????387982??2009-12-03?12:06??image1\實習3.bmp

?????目錄??????????0??2010-01-04?21:45??image1

-----------?---------??----------?-----??----

??????????????3146287????????????????????9


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