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基于博弈論的認(rèn)知無(wú)線電無(wú)線資源分配MATLAB程序

資源截圖

代碼片段和文件信息


clc?
clear?all?
?
B=15;?
BER=10^(-4);?
K=1.5/(logm(0.2/BER));?
SNR=[810];?
k=log2(1+K.*SNR);?
r1=10;?
r2=12;?
x=0;?
y=1;?
z=1;?
%?b=[00];?
%?c=x+y*(sum(b));?
%?p=r.*k.*b-b.*c;?
?
a(1)=0.001;?
for?i=1:300?
????a(2)=0.001;?
????for?j=1:300?
????????eigenvalue(1)=1-10/3*(2*a(1)*k(1)-a(1)*k(2)+2*a(2)*k(2)-a(2)*k(1))+10/3*((a(1)*(k(2)-2*k(1))*a(2)*(k(1)-2*k(2))+(2*a(2)*k(2)-a(2)*k(1)-2*a(1)*k(1)+a(1)*k(2))^2)^(0.5));?
????????eigenvalue(2)=1-10/3*(2*a(1)*k(1)-a(1)*k(2)+2*a(2)*k(2)-a(2)*k(1))-10/3*((a(1)*(k(2)-2*k(1))*a(2)*(k(1)-2*k(2))+(2*a(2)*k(2)-a(2)*k(1)-2*a(1)*k(1)+a(1)*k(2))^2)^(0.5));?
????????if?(eigenvalue(1)<1)&&(eigenvalue(1)>-1)&&(eigenvalue(2)<1)&&(eigenvalue(2)>-1)?
????????????a(2)=a(2)+0.002;?
????????end?
????end?
????if?a(2)>0?
????????a(2)=a(2)-0.002;?
????else?
????????a(2)=0;?
????end?
????f2(i)=a(2);?
????f1(i)=a(1);?
????a(1)=a(1)+0.002;?
end?
?
figure(1)?
plot(f1f2‘--r‘)?
axis([00.2500.25])?
hold?on?
?
B=15;?
BER=10^(-4);?
K=1.5/(logm(0.2/BER));?
SNR=[1010];?
k=log2(1+K.*SNR);?
r1=10;?
r2=12;?
x=0;?
y=1;?
z=1;?
%?b=[00];?
%?c=x+y*(sum(b));?
%?p=r.*k.*b-b.*c;?
?
a(1)=0.001;?
for?i=1:300?
????a(2)=0.001;?
????for?j=1:300?
????????eigenvalue(1)=1-10/3*(2*a(1)*k(1)-a(1)*k(2)+2*a(2)*k(2)-a(2)*k(1))+10/3*((a(1)*(k(2)-2*k(1))*a(2)*(k(1)-2*k(2))+(2*a(2)*k(2)-a(2)*k(1)-2*a(1)*k(1)+a(1)*k(2))^2)^(0.5));?
????????eigenvalue(2)=1-10/3*(2*a(1)*k(1)-a(1)*k(2)+2*a(2)*k(2)-a(2)*k(1))-10/3*((a(1)*(k(2)-2*k(1))*a(2)*(k(1)-2*k(2))+(2*a(2)*k(2)-a(2)*k(1)-2*a(1)*k(1)+a(1)*k(2))^2)^(0.5));?
????????if?(eigenvalue(1)<1)&&(eigenvalue(1)>-1)&&(eigenvalue(2)<1)&&(eigenvalue(2)>-1)?
????????????a(2)=a(2)+0.002;?
????????end?
????end?
????if?a(2)>0?
????????a(2)=a(2)-0.002;?
????else?
????????a(2)=0;?
????end?
????f2(i)=a(2);?
????f1(i)=a(1);?
????a(1)=a(1)+0.002;?
end?
?
figure(1)?
plot(f1f2‘-.*b‘)?
axis([00.2500.25])?
?
B=15;?
BER=10^(-4);?
K=1.5/(logm(0.2/BER));?
SNR=[108];?
k=log2(1+K.*SNR);?
r1=10;?
r2=12;?
x=0;?
y=1;?
z=1;?
%?b=[00];?
%?c=x+y*(sum(b));?
%?p=r.*k.*b-b.*c;?
?
a(1)=0.001;?
for?i=1:300?
????a(2)=0.001;?
????for?j=1:300?
????????eigenvalue(1)=1-10/3*(2*a(1)*k(1)-a(1)*k(2)+2*a(2)*k(2)-a(2)*k(1))+10/3*((a(1)*(k(2)-2*k(1))*a(2)*(k(1)-2*k(2))+(2*a(2)*k(2)-a(2)*k(1)-2*a(1)*k(1)+a(1)*k(2))^2)^(0.5));?
????????eigenvalue(2)=1-10/3*(2*a(1)*k(1)-a(1)*k(2)+2*a(2)*k(2)-a(2)*k(1))-10/3*((a(1)*(k(2)-2*k(1))*a(2)*(k(1)-2*k(2))+(2*a(2)*k(2)-a(2)*k(1)-2*a(1)*k(1)+a(1)*k(2))^2)^(0.5));?
????????if?(eigenvalue(1)<1)&&(eigenvalue(1)>-1)&&(eigenvalue(2)<1)&&(eigenvalue(2)>-1)?
????????????a(2)=a(2)+0.002;?
????????end?
????end?
????if?a(2)>0?
????????a(2)=a(2)-0.002;?
????else?
????????a(2)=0;?
????end?
????f2(i)=a(2);?
????f1(i)=a(1);?
????a(1)=a(1)+0.002;?
end?
?
figure(1)?
plot(f1f2‘-g‘)?
axis([00.2500.25])?
?
?
B=15;?
BER=10^(-4);?
K=1.5/(logm(0.2/BER));?
SNR=[77];?
k=log2(1+K.*SNR);?
r1=10;?
r2=12;?
x=0;?

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件????????4921??2020-09-23?07:56??cognitive_gaming.m

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