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資源簡介

matlab實現的對統計數據進行威布爾分布的估計,并對其進行三參數的評估與計算

資源截圖

代碼片段和文件信息

t=[17.8?21.3?23.8?25.9?27.4?29.4?30.6?32.3?33.5?34.9?36.6?38.5?39.7?41.2?43.4?44.5?47?48.8?52.5?61.4];
n=numel(t);
crep=3000;
r=0;
for?j=3:crep
for?i=1:n
????f(i)=(i-0.3)/(n+0.4);
????y(i)=log(log(1/(1-f(i))));
????x(i)=log(t(i)-r);
end
for?i=1:n
????c1(i)=(x(i)-mean(x))*(y(i)-mean(y));
????c2(i)=(x(i)-mean(x))^2;
end
c3(j)=sum(c1)/sum(c2);
c=c3(j);
d1(j)=exp(-mean(y)/c+mean(x));
d=d1(j);
?for?i=1:n???
Q_old(i)=(t(i)-r-d*(-log(1-f(i)))^(1/c)).^2;???
r1(i)=(t(i)-d*(-log(1-f(i)))^(1/c))/n;
?end
r2(j)=sum(r1);
Q(j)=sum(Q_old);
r=r2(j);
if?Q(j-2)>Q(j-1)&Q(j-1)<=Q(j)
????break
end?
end
canshu=[d?c?r];
for?i=1:n
Ms_yx(i)=(y(i)-(c*x(i)-c*log(d)))^2;
end
Ms_yx1=sum(Ms_yx);
for?j=3:crep
for?i=1:n
????f(i)=(i-0.3)/(n+0.4);
????y(i)=log(log(1/(1-f(i))));
????x(i)=log(t(i)-r);
end
for?i=1:n
????c1(i)=(y(i)-mean(y))^2;
????c2(i)=(x(i)-mean(x))*(y(i)-mean(y));
end
c3(j)=sum(c1)/sum(c2);
c=c3(j);
d1(j)=exp(mean(x)-mean(y)/c);
d=d1(j);
?for?i=1:n???
Q_old(i)=(t(i)-r-d*(-log(1-f(i)))^(1/c)).^2;???
r1(i)=(t(i)-d*(-log(1-f(i)))^(1/c))/n;
?end
r2(j)=sum(r1);
Q(j)=sum(Q_old);
r=r2(j);
if?Q(j-2)>Q(j-1)&Q(j-1)<=Q(j)??
????break
end
end
canshu1=[d?c?r];
for?i=1:n
Ms_xy(i)=(x(i)-(log(d)+y(i)/c))^2;
end
Ms_xy1=sum(Ms_xy);
if?Ms_xy1>Ms_yx1
????true=canshu;
else
????true=canshu1;???
end
fprintf(‘\n位置參數為:%f‘true(1));
fprintf(‘\n形狀參數為:%f‘true(2));
fprintf(‘\n尺度參數為:%f‘true(3));

?屬性????????????大小?????日期????時間???名稱
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?????文件???????1463??2014-05-10?17:13??新建文件夾\Three?parameters?complete?data?about?the?least?square?method.m

?????文件????????395??2014-04-22?18:28??新建文件夾\Untitled2.m

?????目錄??????????0??2014-05-14?03:05??新建文件夾

-----------?---------??----------?-----??----

?????????????????1858????????????????????3


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