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matlab程序求解供應鏈網絡問題。使用變分不等式發
代碼片段和文件信息
function?duozhunze(?)
clc
clear
syms?q111?q112?q121?q122?q211?q212?q221?q222??????????????????????????????????????%%%%%%%%%%%%%?qlij?生產量%%%%%%%%%
syms?p111?p112?p121?p122?p211?p212?p221?p222??????????????????????????????????????%%%%%%%%%%%%零售商售價plij
syms?a111?a112?a121?a122?a211?a212?a221?a222??????????????????????????????????????%購買的概率alij
syms?F111?F112?F121?F122?F211?F212?F221?F222
q1=[q111q112;q121q122];??????????????????????????????????%%%%%%%生產量%%%%%
q2=[q211q212;q221q222];
p1=[p111p112;p121p122];?????????????????????????????????????????%消費者購買的總支出plij
p2=[p211p212;p221p222];
b=[1010;1010];
gi=[22;22];??????????????????????????????%%生產商的廣告投入
gj=[33;33];????????????????????????????%%零售商的廣告投入
%%%%%%%%%%%%%%%%%%%%%函數%%%%%%%%%%%%%%%%%%%%%%%%%%%%
??????%%%%%%%%%%%?fli?生產商生產成本%%%%%%%%%%
f11=1*(q111+q112)^2+(q111+q112)*(q121+q122)+2*(q111+q112);
f12=1*(q121+q122)^2+(q121+q122)*(q111+q112)+2*(q121+q122);
f21=2.5*(q211+q212)^2+2*(q211+q212)*(q221+q222)+(q211+q212);
f22=3*(q221+q222)^2+2*(q211+q212)*(q221+q222)+(q221+q222);
%%%%%%%%%%?fmij?%%%%%%%%%%%
f111=0.5*(q111)^2+2*q111;
f112=0.5*(q112)^2+2*q112;
f121=0.5*(q121)^2+2*q121;
f122=0.5*(q122)^2+2*q122;
f211=1*(q211)^2+2*q211;
f212=1*(q212)^2+2*q212;%%%%
f221=1.5*(q221)^2+2*q221;
f222=1.5*(q222)^2+2*q222;
%零售商銷售成本函數clj
c11=1*(q111+q121)^2;???c12=1*(q112+q122)^2;
c21=2*(q211+q221)^2;???c22=2.5*(q212+q222)^2;??
%零售商廣告投入成本
A11=gj(11)*(q111+q121);
A12=gj(12)*(q112+q122);
A21=gj(21)*(q211+q221);
A22=gj(22)*(q212+q222);
%%%%%%alij?消費者購買的概率%%%
a111=exp(-0.5*(p111-gi(11)))/(exp(-0.5*(p111-gi(11)))+exp(-0.5*(p121-gi(12))));
a112=exp(-0.5*(p112-gi(11)))/(exp(-0.5*(p112-gi(11)))+exp(-0.5*(p122-gi(12))));
a121=exp(-0.5*(p121-gi(12)))/(exp(-0.5*(p111-gi(11)))+exp(-0.5*(p121-gi(12))));
a122=exp(-0.5*(p122-gi(12)))/(exp(-0.5*(p112-gi(11)))+exp(-0.5*(p122-gi(12))));
a211=exp(-0.5*(p211-gi(21)))/(exp(-0.5*(p211-gi(21)))+exp(-0.5*(p221-gi(22))));
a212=exp(-0.5*(p212-gi(21)))/(exp(-0.5*(p212-gi(21)))+exp(-0.5*(p222-gi(22))));
a221=exp(-0.5*(p221-gi(22)))/(exp(-0.5*(p211-gi(21)))+exp(-0.5*(p221-gi(22))));
a222=exp(-0.5*(p222-gi(22)))/(exp(-0.5*(p212-gi(21)))+exp(-0.5*(p222-gi(22))));
%%%%平均價格plj
p11=a111*p111+a121*p121;
p12=a112*p112+a122*p122;
p21=a211*p211+a221*p221;
p22=a212*p212+a222*p222;
?%%%%%%%%%%%%qlij零售商與需求市場的交易量%%%%%%%%%%%%%%%%%%%%%%
ql111=q111-(p11*(q111)^2)/(2*a111*(b(11)+10*A11));
ql112=q112-(p12*(q112)^2)/(2*a112*(b(12)+10*A12));
ql121=q121-(p11*(q121)^2)/(2*a121*(b(11)+10*A11));
ql122=q122-(p12*(q122)^2)/(2*a122*(b(12)+10*A12));
ql211=q211-(p21*(q211)^2)/(2*a211*(b(21)+10*A21));????
ql212=q212-(p22*(q212)^2)/(2*a212*(b(22)+10*A22));
ql221=q221-(p21*(q221)^2)/(2*a221*(b(21)+10*A21));???
ql222=q222-(p22*(q222)^2)/(2*a222*(b(22)+10*A22));
%%%%%%隨機需求Flij%%%%%%%%%%%
F111=(q111)*p11/(a111*(b(11)+10*A11));
F112=(q112)*p12/(a112*(b(12)+10*A12));
F121=(q121)*p11/(a121*(b(1
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????8327??2012-09-14?21:17??guanggao.m
-----------?---------??----------?-----??----
?????????????????8327????????????????????1
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