資源簡介
對陣列信號進行相關處理,得到信源個數(shù),并可以估計出信源發(fā)射過來的角度,以便于測出目標的位置

代碼片段和文件信息
function[P1]=Beamforming(Rdth1)
R;
th1=[-90:1:90];
l=length(th1);
P1=zeros(1l);
k=0;
M=1/10^1/2;
e=(90-(-90))/length(th1);
for?i=1:length(th1);
????a1=exp(-j*pi*d*sin((-90+i*e)*pi/180)).‘;
????a=bsxfun(@timesa1M);
????p=(a‘*R*a)/(a‘*a);
????P1(1(k+1))=p;
????k=k+1;
end
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????291??2012-12-18?10:06??music&root?music\Beamforming.m
?????文件???????1583??2012-12-18?10:53??music&root?music\BeamMAIN.m
?????文件????????276??2012-12-17?01:38??music&root?music\copen1.m
?????文件????????320??2012-12-18?10:05??music&root?music\ESPRIT.m
?????文件???????1241??2012-12-18?10:12??music&root?music\esprit_main.m
?????文件????????494??2012-12-18?10:52??music&root?music\root.m
?????目錄??????????0??2013-07-17?21:41??music&root?music
-----------?---------??----------?-----??----
?????????????????4205????????????????????7
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