資源簡介
主要使用電腦給單片機發送字符串和數字 并通過串口軟件返回電腦 同時也用到了簡單加密和檢驗設計
適合單片機初學者下載

代碼片段和文件信息
//給數碼管發送“0-65535“之間的任意數據
//然后返回給電腦
#include
#define?uint?unsigned?int
#define?uchar?unsigned?char
uchar?aflagi;
uchar?num;
uchar?buf[2];
uchar?code?table[]={0x3f0x060x5b0x4f0x66
0x6d0x7d0x070x7f0x6f};//此數組為??!!!??0~9???!!!
void?main()
{
?TMOD=0x20;//定時器1工作方式2
?TH1=0xFD;
?TL1=0XFD;//設置9600波特率
?TR1=1;
?REN=1;
?SM0=0;
?SM1=1;//工作方式1
?EA=1;
?ES=1;
?while(1)
?{
??if(flag)
??{
???ES=0;
for(i=0;i<14;i++)
{
SBUF=buf[i];
while(!TI);
TI=0;
}
ES=1;
flag=0;
??}
?}
}
void?series()?interrupt?4
{
???RI=0;
??for(i=0;i<2;i++)
????{
?buf[i]=SBUF;
?RI=0;
?}
a=buf[0]*256+buf[1];
flag=1;
}
void?disp_num(uint?aa)
{
?uchar?wanqianbaishige;
?wan=aa/10000;
?qian=aa/1000%10;
?bai=aa/100%10;
?shi=aa/10%10;
?ge=aa%10;
}
void?disp_7seg()
{
switch(num)
{
?case?0:P2=table[0];break;
?case?1:P2=table[1];break;
?case?2:P2=table[2];break;
?case?3:P2=table[3];break;
?case?4:P2=table[4];break;
?case?5:P2=table[5];break;
?case?6:P2=table[6];break;
?case?7:P2=table[7];break;
?case?8:P2=table[8];break;
?case?9:P2=table[9];break;
?default:break;
}
}
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????3689??2009-04-18?14:57??series\series_1.LST
?????文件????????187??2009-05-16?11:06??series\series_1.plg
?????文件???????5187??2009-04-18?14:57??series\series_1.OBJ
?????文件???????1242??2009-04-18?14:57??series\series_1.c
?????文件???????4514??2009-04-18?14:57??series\series_1
????.......???????983??2009-04-18?15:01??series\series_1_Opt.Bak
?????文件?????????48??2009-04-18?14:57??series\series_1.lnp
?????文件???????6846??2009-04-18?14:57??series\series_1.M51
?????文件????????981??2009-05-16?10:40??series\series_1.Opt
?????文件???????1223??2009-04-18?14:57??series\series_1.hex
????.......?????????0??2009-04-10?14:29??series\series_1_Uv2.Bak
?????文件???????2124??2009-04-10?15:36??series\series_1.Uv2
?????文件????????512??2009-04-10?16:00??series\series_1_shumaguan.c
?????文件????????656??2009-04-10?16:14??series\series_secret.c
?????目錄??????????0??2009-04-10?14:28??series
-----------?---------??----------?-----??----
????????????????28192????????????????????15
- 上一篇:云安全技術與應用試題
- 下一篇:FlashFXP最新 注冊碼 注冊機
評論
共有 條評論