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%?2009.8.29?閱讀此段程序收獲如下：
%?1.在已經估計出導頻點位置的信道相應后，如何進行插值。
%???利用函數“interp1“實現一維插值，還可以利用“interpN“實現高維插值
%?2.另一個亮點是，實現瑞利信道的過程。
%???SISO系統，六徑，因此每個路徑都有延時，而G的增益也有六個。
%???利用插值實現延時和增益，不錯的概念。
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%16QAM-OFDM?system;
clear?all;
clear?all;

N?=?1024;????????????????????????????????????????????????????????%the?total?number?of?all?subcarriers
Np?=?128;?????????????????????????????????????????????????????????%the?number?of?pilot?carriers
B?=?2e6;?????????????????????????????????????????????????????????%bandwidth?2MHz
T?=?1/B;
Ng?=?256;????????????????????????????????????????????????????????%the?length?of?Guard?Interval
Xp?=?3?+?1.0*j?;???????????????????????????????

?屬性????????????大小?????日期????時間???名稱
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?????文件??????74108??2009-01-23?23:30??瑞利信道LS信道估計\license.dat

?????文件???????4888??2009-08-29?11:24??瑞利信道LS信道估計\OFDM_LS_directly.asv

?????文件???????4991??2009-08-29?11:26??瑞利信道LS信道估計\OFDM_LS_directly.m

?????文件????????657??2005-09-12?18:52??瑞利信道LS信道估計\ray_channel.m

?????目錄??????????0??2010-04-27?10:27??瑞利信道LS信道估計

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????????????????84644????????????????????5