clc
close?all
clear
tic
%?m=input（‘請輸入種群中的個體數(shù)量?m=‘）;
%?n=input（‘請輸入二進制編碼位數(shù)（推薦16位）?n=‘）;
%?t=input（‘請輸入自變量個數(shù)?t=‘）;
%?a=input（‘請輸入學習速率?a=‘）
m=100
n=32;t=2;
x=zeros（tnm）;
X=zeros（tm）;a=0.01;
%?[mn]=size（x（1））;
for?k=1:1:m
????for?i=1:1:t
????????for?j=1:1:n
????????????x（ijk）=round（rand（））;
????????end
????end
end
I=1;
Imax=20;
p=zeros（tImaxn）;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
while?I<=Imax?%總循環(huán)
????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%生成新一代
????if?I>1
????????for?j=1:n
????????????p（:Ij）=（1-a）.*p（:I-1j）+a.*x（:jindex（m））;
????????end
????????for?i=1:m
????????????for?j=1:n
????????????????for?k=1:t
????????????????????temp=rand;
????????????????????if?temp????????????????????????x（kji）=1;
????????????????????else
????????????????????????x（kji）=0;
????????????????????end
????????????????end
????????????end
????????end
????end
????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%譯碼為十進制數(shù)
????for?i=1:m
????????for?k=1:t
????????????temp=zeros（1t）;
????????????for?j=1:n
????????????????temp（k）=temp（k）+x（kji）*2^（j-1）
%?????????????????X（ki）=（temp+x（kij）*2^（j-1）/（2^n-1））*10-5;
????????????end
????????????X（ki）=temp（k）/（2^n-1）*10-5;
????????end
????end
????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%計算目標函數(shù)
????for?i=1:m
????????