clcclear?
fid=fopen（‘txt3.txt‘‘r‘）;
n1=6;
n2=3;
a=[];
for?i=1:n1
?tmp=str2num（fgetl（fid））;
?a=[a;tmp];?%讀準則層判斷矩陣
end
for?i=1:n1?
????str1=char（[‘b‘int2str（i）‘=[];‘]）;?
????str2=char（[‘b‘int2str（i）‘=[b‘int2str（i）‘;tmp];‘]）;
????eval（str1）;
??for?j=1:n2
????tmp=str2num（fgetl（fid））;
????eval（str2）;?%讀方案層的判斷矩陣
??end
end
ri=[000.580.9