資源簡介
STA-LTA 長短視窗處理地震信號算法
代碼片段和文件信息
clc;
clear;
Ap=0.3;fp=300;Np=300;h=-150;dt=0.0005;
As=1;fs=200;Ns=450;
for?i=300:1000
?A1(i)=Ap*exp(h*(i*dt-Np*dt))?*sin(2*pi*fp*(i*dt-Np*dt));
end
for?i=450:1000
?????A2(i)=-As*exp(h*(i*dt-Ns*dt))?*sin(2*pi*fs*(i*dt-Ns*dt));
end
for?i=1:1000
s(i)=A1(i)+A2(i);
end
?
NOISE=randn(size(s));
Y=s+0.03*NOISE;
A=abs(Y);
for?i=180:1000
????LTA1(i)=0;
????for?n=i-60+1:i
????LTA1(i)=LTA1(i)+A(n)*A(n);
????end?
end
for?i=180:1000
????LTA3(i)=0;
????for?n=i-180+1:i
????LTA3(i)=LTA3(i)+A(n)*A(n);
????end?
end
for?i=180:1000
????STA(i)=0;
????for?n=i-20+1:i
???STA(i)=STA(i)+A(n)*A(n);
????end?
end
sta=STA./20;
r1=3.*STA./LTA1;
lta1=LTA1./60;
r3=9.*STA./LTA3;
lta3=LTA3./180;
THR(1:1000)=3;
figure(1)
subplot?511?;plot(Y);xlim(
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????1436??2016-04-25?21:08??duanshic.m
?????文件?????????933??2016-04-25?21:21??jianquanmer.m
?????文件?????????588??2016-04-25?21:20??jiaquanxishu(1).m
?????文件????????1228??2016-04-25?17:28??lta.m
?????文件????????1224??2016-04-25?21:34??CHANG.m
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