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資源簡介

切比雪夫(Chebyshev)多項式展開式的matlab程序,輸入一個函數 可以很方便直接得到切比雪夫的展開式

資源截圖

代碼片段和文件信息

function?f=Chebyshev(ykx0)
%用切比雪夫多項式逼近已知函數?%已知函數:y?
%逼近已知函數所需項數:k?%逼近點的x坐標:x0?
%求得的切比雪夫逼近多項式或在x0處的逼近值:f??

syms?t;
T(1:k+1)=t;
T(1)=sym(‘1‘);
T(2)=t;
c(1:k+1)=sym(‘0‘);
c(1)=int(subs(yfindsym(sym(y))sym(‘t‘))*T(1)/sqrt(1-t^2)t-11)/pi;
c(2)=2*int(subs(yfindsym(sym(y))sym(‘t‘))*T(2)/sqrt(1-t^2)t-11)/pi;f=c(1)+c(2)*t;
????for?i=3:k+1
?????T(i)?=?2*t*T(i-1)-T(i-2);?
??????c(i)?=?2*int(subs(yfindsym(sym(y))sym(‘t‘))*T(i)/sqrt(1-t^2)t-11)/2;????
??????f?=?f?+?c(i)*T(i);?????
??????f?=?vpa(f6);??????
????if(i==k+1)?
????????if(nargin?==?3)?
????????????f?=?subs(f‘t‘x0);?????????
???????????else?
????????????f?=?vpa(f6);?????????
??????????????end?????
?????????????????end?
????????????????????end

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????800??2014-03-28?19:57??Chebyshev.m

?????文件????????886??2014-04-02?15:24??ChebyshevPoly.m

?????文件????????131??2014-04-14?21:41??redeme.txt

-----------?---------??----------?-----??----

?????????????????1817????????????????????3


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