%---------------------------------------------------------------------------------------------
%2?遍歷得到各點(diǎn)的積分
function?ii?=?bianli（I）

%I=[123456;789101112;131415161718;192021222324;252627282930;313233343536];%測(cè)試矩陣2
I=imread（‘cameraman.tif‘）;

[rowcol]?=?size（I）;
ii=zeros（rowcol）;
for?i=1:row
for?j=1:col
?????s=sum（I（1:ij））;
?????if（j-1<=0）
???????ii（ij）?=?s;
?????else
????????ii（ij）=s+ii（ij-1）;
?????end
?????s=0;
???end
end
ii=buzero（ii11）;
F=tezhen1（ii）;

%---------------------------------------------------------------------------------------------
%3?在矩陣上面補(bǔ)0和左面補(bǔ)0
%rn?補(bǔ)rn行0
%cn?補(bǔ)cn列0

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件????????693??2013-11-10?21:24??haar-like\bianli.m

?????文件????????226??2013-11-10?21:19??haar-like\buzero.m

?????文件????????388??2013-11-10?21:25??haar-like\haar.m

?????文件????????635??2013-11-10?21:20??haar-like\tezhen1.m

?????目錄??????????0??2013-11-10?21:28??haar-like

-----------?---------??----------?-----??----

?????????????????1942????????????????????5