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控制增益符號已知/未知的MIMO時滯系統的自適應控制

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代碼片段和文件信息

%~~~~~~~~~~~~~~~~~~~~~~~?function?for?p6main.m?~~~~~~~~~~~~~~~~~~~~~~~~
function?f=directp01fun(tx)?
global?e1
global?u1
%--------------Neural?network?control?tpzhang------?initialize?---------
f=zeros(581);
gama=0.5;
k1=1;
k2=1;
Mf=4;
wm=0.001;
eps=1;
eta1=0.01;eta2=0.01;eta3=0.01;eta=0.01;
xd1=[pi*sin(t)/30pi*cos(t)/30]‘;
x1=[x(1)?x(2)]‘;
K1=x(3:5);
W1=x(6:15);
V1=zeros(410);
for?i=1:10
???V1(:i)=x(4*i+12:4*i+15);
end
%-------------------------?error?&?swith?function?---------------------
e1=xd1-x1;
sigama=k1*e1(2)+k2*e1(1)-pi*sin(t)/30;
%-------------------------?fuzzy?base?function?------------------------
z1=[x(1)?x(2)?sigama]‘;
zbar1=[z1‘?1]‘;

ds1=zeros(101);
hats1=zeros(101);
for?i=1:10
???ds1(i)=(gama*exp(-gama*V1(:i)‘*zbar1))/(1+exp(-gama*V1(:i)‘*zbar1))^2;
???hats1(i)=1/(1+exp(-gama?*V1(:i)‘*zbar1));
end

%//i?rules?&?vector?z(j);?i=5;?j=7//?
ph1=zeros(31);
ph1=[norm(zbar1*W1‘*diag(ds1)‘fro‘)?norm(diag(ds1)*V1‘*zbar1)?1]‘;
un=W1‘*hats1;

?
%----------------------------?control?law?-----------------------------
Fx=15.78+0.0366*x(2)^2;
Dx=1.2;
vbar=4;
bL=1.12;p=[15?5;5?5];
Q=[10?0;0?10];pn=[5?5]‘;
%define?sat?function
phi1=0.001;
y=e1‘*pn/phi1;
if?y<=-1?
????sat1=-1;
elseif?abs(y)<=1
????sat1=y;
else?
????sat1=1;
end

ve=e1‘*p*e1;
if?ve>2*vbar
???Ivbar=1;
else?
???Ivbar=0;
end
?xtal2=zeros(401);
?xtal=zeros(150001);
?bx=abs(0.3*cos(x(1)));
if?t-1-0.5*sin(t)<=0
???delta=0.1*x(1)^2;
???b1x=delta+bx;
else
???for?q=1:40?
?????for?m=(375*(q-1)+1):(375*q);
???????b1x=bx+xtal2(q);
?????end
???end
end
hmax=0.2;
?uc=(K1‘*ph1+(Dx+x(56)+b1x)/bL)*sat1;
?us=Ivbar*sat1*(abs(un)+(hmax+b1x+Fx+abs(-pi*sin(t)/30)+abs(k1*e1(2)+k2*e1(1)))/bL);
?u1=un+uc+us;
??
%------------------------------?equation?------------------------------
j=1;
f(1)=x(2);
if?t-1-0.5*sin(t)<=0
???f(2)=(9.8*sin(x(1))-0.05*x(2)^2*cos(x(1))*sin(x(1))/1.1)/(2/3-0.05*(cos(x(1)))^2/1.1)...
???+((cos(x(1))/1.1)/(2/3-0.05*(cos(x(1)))^2/1.1))*u1+0.3*cos(x(1))+0.1*x(1)^2;
???N=375;
????for?i=1:N
????????xtal(i)=x(1);
????????xtal2(1)=0.05;
????????if?xtal2(1)<=abs(xtal(i))
????????????xtal2(1)=abs(xtal(i));
????????end
????end
else
???f(2)=(9.8*sin(x(1))-0.05*x(2)^2*cos(x(1))*sin(x(1))/1.1)/(2/3-0.05*(cos(x(1)))^2/1.1)...
???+((cos(x(1))/1.1)/(2/3-0.05*(cos(x(1)))^2/1.1))*u1+0.3*cos(x(1))+0.1*xtal(j)^2;
???j=j+1;
%????for?i=1501:40000
%???????xtal(i)=x(1);
??????for?k=1:39;
????????for?l=(375*k+1):(375*(k+1));
????????????xtal(l)=x(1);
????????????xtal2(k+1)=0.05;
????????????if?xtal2(k+1)<=abs(xtal(l))
????????????????xtal2(k+1)=abs(xtal(l));
????????????end
????????end
??????end
%?????end
end
f(3:5)=eta3*abs(e1‘*pn)*ph1;

norm1=0;
for?i=6:15
???norm1=x(i)‘*x(i)+norm1;
end
norm1=sqrt(norm1);

if?norm1=0)?
?????f(6:15)=eta1*(hats1-diag(ds1)*V1‘*zbar1)*e1‘*pn;
???else??
?????f(6:15)=eta1*(hats1-diag(ds1)*V

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????5141??2010-03-26?17:57??p102fun.m

?????文件???????3198??2010-03-26?18:00??p102main.m

?????文件???????3188??2008-04-05?09:23??directp01fun.m

?????文件???????2577??2008-04-04?21:19??directp01main.m

-----------?---------??----------?-----??----

????????????????14104????????????????????4


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