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捷聯慣導系統靜基座初始對準 MATLAB

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代碼片段和文件信息

%%%%%%%%%%%采用東北天坐標系%%%%%%%%%%%%%%
%%%%%%%%%%%%初始對準仿真%%%%%%%%%%%%%%%%%
%%%%%%%%%%%加速度計的零偏和陀螺漂移都考慮的情況%%%%%%%%%%%%%%%


%%%%%%%%%%%%%%給定常數%%%%%%%%%%%%%%%%%%%

%初始姿態角(rad)
yaw_origin?=?0;
roll_origin?=?0;
pitch_origin?=?0;

N?=?5000;%仿真時間
deg?=?pi/180;%一度對應的弧度
latitude_origin?=?45*deg;%初始緯度(rad)
g?=?9.84;%地球重力加速度(m/s2)
Wie?=?7.2916e-5;%地球自轉角速度(rad/s)
%艦船初始速度(m/s)
VE_origin?=?0;
VN_origin?=?0;

%初始失準角
PE_origin?=?deg;
PN_origin?=?deg;
PU_origin?=?deg;

%慣性器件的隨機和常值漂移
Gyro_cons?=?0.02*deg/3600;
Gyro_rand?=?0.01*deg/3600;

Acce_cons?=?100e-6*g;
Acce_rand?=?50e-6*g;

%%%%%%%%設置Kalman濾波器的初始值%%%%%%%%
X0r?=?[0.10.1degdegdeg100e-6*g100e-6*g0.02*deg/36000.02*deg/36000.02*deg/3600]‘;%狀態初值,真實值
X0e?=?[0000000000]‘;%狀態估計初值
Q0?=?diag([(50e-6*g)^2?(50e-6*g)^2?(0.01*deg/3600)^2?(0.01*deg/3600)^2?(0.01*deg/3600)^2?0?0?0?0?0]);
P0?=?diag([(0.1)^2?(0.1)^2?(deg)^2?(deg)^2?(deg)^2?(100e-6*g)^2(100e-6*g)^2(0.02*deg/3600)^2(0.02*deg/3600)^2(0.02*deg/3600)^2]);
R?=?diag([(0.1)^2?(0.1)^2]);

%%%%%%%%%%%%%%%%根據慣導誤差方程列些狀態方程%%%%%%%%%%%%%%%%%%
Ou?=?Wie*sin(latitude_origin);
On?=?Wie*cos(latitude_origin);
F?=?[0?2*Ou?0?-g?0;
????-2*Ou?0?g?0?0;
????0?0?0?Ou?-On;
????0?0?-Ou?0?0;
????0?0?On?0?0];
Ci?=?eye(5);%姿態矩陣寫成單位矩陣表示載體坐標系和導航坐標系重合
Ci?=[0.9994?0.0177?0?0?0;
????-0.0171?0.9994?0?0?0;
????0?0?0.9994?0.0177?-0.0171;
????0?0?-0.0171?0.9994?0.0177;
????0?0?0.0177?-0.0171?0.9994];
A?=?[F?Ci;
?????zeros(55)?zeros(55)];
B?=?eye(10);
H?=?[eye(2)?zeros(28)];
D?=?zeros(210);
%%%%%%%%%%%%%%%%%%對連續模型進行離散化的處理%%%%%%%%%%%%%%%%%
G?=?ss(ABHD);
T?=?1;
GD?=?c2d(GT);
PHI?=?GD.a;%%%%%離散化后的狀態轉移矩陣也可以寫成expm(A*T)
Xout?=?zeros(10N);

%%%%%%%%%%%%%%%%%%%%進入濾波器的計算%%%%%%%%%%%%%%%%%%%%%%%%%
Xrk_1?=?X0r;
Xk_1?=?X0e;
Pk_1?=?P0;
for?i?=?1:N
??Z?=?H*Xrk_1?+?(mvnrnd([0;0]R1))‘;??
??Pkk?=?PHI*Pk_1*PHI‘?+?Q0;%一步方差預測
??K?=?Pkk*H‘*inv(H*Pkk*H‘?+?R);%濾波增益
??Pk?=?(eye(10)-K*H)*Pkk;????%估計均方誤差
??Xk?=?PHI*Xk_1;??%一步預測
??Xk?=?Xk?+?K*(Z?-?H*Xk);
??%Xk?=?Xk;
??Xout(:i)?=?Xk;
??Xk_1?=?Xk;
??Pk_1?=?Pk;
??%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
??%%%%%%%%%%%%%%%估計出失準角應該更新姿態矩陣%%%%%%%%%%%%%%%%
??Ci(33)?=?Ci(33)?-?Xout(5i)*Ci(43)?+?Xout(4i)*Ci(53);
??Ci(34)?=?Ci(34)?-?Xout(5i)*Ci(44)?+?Xout(4i)*Ci(54);
??Ci(35)?=?Ci(35)?-?Xout(5i)*Ci(45)?+?Xout(4i)*Ci(55);
??
??Ci(43)?=?Xout(5i)*Ci(33)?+?Ci(43)?-?Xout(3i)*Ci(53);
??Ci(44)?=?Xout(5i)*Ci(34)?+?Ci(44)?-?Xout(3i)*Ci(54);
??Ci(45)?=?Xout(5i)*Ci(35)?+?Ci(45)?-?Xout(3i)*Ci(55);
??
??Ci(53)?=?-Xout(4i)*Ci(33)?+?Xout(3i)*Ci(43)?+?Ci(53);
??Ci(54)?=?-Xout(4i)*Ci(34)?+?Xout(3i)*Ci(44)?+?Ci(54);
??Ci(55)?=?-Xout(4i)*Ci(35)?+?Xout(3i)*Ci(45)?+?Ci(55);
??%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
???Ci?=?[Ci(33)?Ci(34)?0?0?0;
????????Ci(43)?Ci(44)?0?0?0;
????????0?0?Ci(33)?Ci(34)?Ci(35);
????????0?0?Ci(43)?Ci(44)?Ci(45);
????????0?0?Ci(53)?Ci(54)?Ci(55)];
??A?=?[F

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????3629??2012-03-03?15:21??qk_AG.m

-----------?---------??----------?-----??----

?????????????????3629????????????????????1


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