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資源簡介

經典的Matlab ICP點云配準算法,含三個可用例子。

資源截圖

代碼片段和文件信息


%?Generate?model?points

xvals=linspace(02*pi500);
yvals=sin(xvals);

model=[xvals;yvals];

%?Generate?data?points

xvals=linspace(02*pi100);
yvals=sin(xvals);

data=[xvals;yvals];

%?Transform?data?points?to?their?start?positions

v1=0.6*(2*rand-1);
Rma=[cos(v1)?-sin(v1);sin(v1)?cos(v1)];

data=Rma*data;
data(1:)=data(1:)+2*randn;
data(2:)=data(2:)+2*randn;

%?A?plot.?Model?points?and?data?points?in?start?positions

figure(1)
plot(model(1:)model(2:)‘r.‘data(1:)data(2:)‘b.‘)?axis?equal

%?Running?the?ICP-algorithm.?Least?squares?criterion

[TRTTdataOut]=icp(modeldata);

%?A?plot.?Model?points?and?data?points?in?transformed?positions

figure(2)
plot(model(1:)model(2:)‘r.‘dataOut(1:)dataOut(2:)‘b.‘)?axis?equal


?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????2654??2015-06-16?04:37??example3.m
?????文件????????8330??2015-06-16?04:37??icp.m
?????文件???????30309??2015-06-16?04:37??icpOLD.m
?????文件????????1639??2015-06-16?04:37??readme.txt
?????文件?????????789??2015-06-16?04:37??example.m
?????文件????????1872??2015-06-16?04:37??example2.m
?????文件????????1314??2015-06-16?04:37??license.txt

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