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  • 大小: 5KB
    文件類型: .m
    金幣: 1
    下載: 0 次
    發(fā)布日期: 2021-05-13
  • 語(yǔ)言: Matlab
  • 標(biāo)簽: lq??

資源簡(jiǎn)介

lqr軌跡跟蹤的matlab編程,是通過(guò)lqr控制器控制,走出一條直線或者圓軌跡

資源截圖

代碼片段和文件信息

%?long=20
%?lati=50
%?
%?A=[-1.4934?0;?0?-0.3038];
%?B=[0;0.0012];
%?C=[0?1];
%?D=[0];
%?E=[00.8];
%?N=100;
%?Ahat=[A?zeros(21)?zeros(21);-C?0?0;-E?0?0];
%?Bhat=[B;0;0];
%?Q=[100?0?0?0;0?1?0?0;0?0?1?0;0?0?0?1?];
%?R=[0.01];
%?KK=lqr(AhatBhatQR)
%?
%?K1=[KK(1)KK(2)];
%?K2=-KK(3);
%?K3=-KK(4);
%?for?i=1:N;
%?????du=-0.7383*x1(i)+0.5565;
%?????x1(i+1)=x1(i)+du;
%?????e(i)=exhead-head(i);
%?????n(i)=15*e(i)-K1*[x2(i);x3(i)];
%????
%?????d=A*[x2(i);x3(i)]+B*n(i);
%?????x2(i+1)=x2(i)+d(1);
%?????x3(i+1)=x3(i)+d(2);
%?????head(i+1)=head(i)+x3(i+1)*1;
%?????u(i+1)=x1(i)*cos(head(i))-x2(i)*sin(head(i));
%?????v(i+1)=x1(i)*sin(head(i))+x2(i)*cos(head(i));
%?????long(i+1)=long(i)+v(i+1)*1;
%?????lati(i+1)=lati(i)+u(i+1)*1;
%?end
%?
%?figure
%?plot(longlati)
%?figure
%?plot(x1)
%?figure
%?plot(x2)
%?figure
%?plot(x3)
%?figure
%?plot(head)
%?figure
%?plot(n)


%?tic
%?2*6/8*4*6*1/5*7*2^5/3^3
%?toc?
%%%%%%%%%%%%%%%%%%%90°直線跟蹤%%%%%%%%%%%%%%%%
%?x1=0;
%?x2=0;
%?x3=0;
%?
%?
%?n=0;%初始轉(zhuǎn)速差
%?
%?long=20;
%?lati=10;%初始位置
%?head=0;%當(dāng)前航向
%?exhead=pi/2;%期望航向
%?
%?K1=[0?31.1923];
%?K2=10;
%?K3=0.4;
%?
%?for?i=1:300;
%?????du=-0.7383*x1(i)+0.5565;
%?????x1(i+1)=x1(i)+du;
%?????e(i)=exhead-head(i);
%?????n(i)=K3*(lati(i))+K2*e(i)-K1*[x2(i);x3(i)];
%????
%?????d=A*[x2(i);x3(i)]+B*n(i);
%?????x2(i+1)=x2(i)+d(1);
%?????x3(i+1)=x3(i)+d(2);
%?????head(i+1)=head(i)+x3(i+1)*1;
%?????u(i+1)=x1(i)*cos(head(i))-x2(i)*sin(head(i));
%?????v(i+1)=x1(i)*sin(head(i))+x2(i)*cos(head(i));
%?????long(i+1)=long(i)+v(i+1)*1;
%?????lati(i+1)=lati(i)+u(i+1)*1;
%?end
%?
%?figure
%?plot(longlati)
%?figure
%?plot(n)

%%%%%%%%%%%%%%%%%%%坐標(biāo)系中任意直線跟蹤%%%%%%%%%%%%%%%%
xx0=20;
yy0=40;%初始位置
xx1=5;
yy1=5;%位點(diǎn)1
xx2=60;
yy2=60;%位點(diǎn)2
head=0;%初始航向



theta2=acosd(dot([xx2-xx1yy2-yy1][01])/(norm([xx2-xx1yy2-yy1])*norm([01])));%位點(diǎn)2與位點(diǎn)1連線與y軸夾角
exhead=theta2*pi/180;
x1=0;
x2=0;
x3=0;
n=0;
%?KK=[5.9583?2.6656?-0.0293];%Q=[1?0?0;0?1?0;0?0?0.01]R=0.1
KK=[6.1597?2.5177?-0.2769];%Q=[1?0?0;0?1?0;0?0?0.1]R=0.1
%?KK=[6.0497?2.5970?-0.1428];%Q=[1?0?0;0?1?0;0?0?0.05]R=0.1

K1=KK(1);
K2=KK(2);
K3=KK(3);

%?A=[-1.4934?0;?0?-0.3038];
%?B=[0;0.0012];
A=[0.7037?0?0;0.8432?1?0;-0.9

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